Найдите точку минимума y=x^2+1000/x

y = x^2 + 1000/xy ' = 2x - 1000/x^2 = (2x^3 - 1000)/x^2 = 2(x^3 - 500)/x^2 = 0x^3 = 500x0 = ∛500 ~ 8 (8^3 = 512)y(x0) = ∛(500^2) + 1000/(∛500) = (500 + 1000)/(∛500) = 1500/(∛500) == 1500*∛(500^2)/500 = 3∛(250000) = 30∛250Ответ: (∛500; 30∛250)