Sin^2(3pi/2-y)+sin^2(3pi+y)+2tg(5pi/2-y)×tg (3pi+y)

Sin^2(3pi/2-y)+sin^2(3pi+y)+2tg(5pi/2-y)×tg (3pi+y)---------------------------------Решение Вычислить Sin²(3π/2-y)+sin²(3π+y)+2tg(5π/2-y)*tg (3π+y) .---Применяя   формулы  приведения ,получаем :Sin²(3π/2-y)+sin²(3π+y)+2tg(5π/2-y)*tg (3π+y)= (cos²y +sin²y)+ 2ctqy*tqy =1 +2*`1 =3.ответ : 3.===========================sin (3π/2-y)) = -cosysin(3π +y ) =sin( (2π+(π +y ) )=sin(π +y ) =  -sinytg(5π/2-y) =tg((2π +(π/2-y) ) =tq(π/2-y) =ctqy tq(3π +y ) =tq( (2π+(π +y ) ) =tq(π +y ) =tqy