Упростить выражение (6/(y^2-9)+1/(3-y))*(y^2+6y+9)/5

...........=( \frac{6}{(y-3)(y+3)} - \frac{1}{y-3})* \frac{(y+3)(y+3)}{5} = \\ \\ \frac{6-y-3}{(y-3)(y+3)}*\frac{(y+3)(y+3) }{5} = \frac{3-y}{5(y-3)}=- \frac{y-3}{5(y-3)}=- \frac{1}{5}= -0.2