ОДЗ{x>0{log(2)x+1≠0⇒log(2)x≠-1⇒x≠1/2x∈(0;0,5) U (0,5;∞)4/(log(2)x+1)-1≤0(4-log(2)x -1)/(log(2x+1)≤0(3-log(2)x)/(log(2)x+1)≤01){3-log(2)x≤0⇒log(2)x≥3⇒x≥8{log(2)x+1>0⇒log(2)x>-1⇒x>0,5x≥82){3-log(2)x≥0⇒log(2)x≤3⇒x≤8{log(2)x+1<0⇒log(2)x<-1⇒x<0,5x<0,5 +ОДЗ⇒0<x<0,5Ответ x∈(0;0,5) U [8;∞)