(3 - х² )² - (5 - х² )² = 0
Помогите

(3 - x^2 - 5 + x^2)(3 - x^2 + 5 - x^2) = 0 - 2 (- 2x^2 + 8) = 0  /: - 2- 2x^2 + 8 = 0   /: - 2x^2 - 4 = 0x^2 = 4x = ± √4x = ± 2 

(3 - х² )² - (5 - х² )² = 0(3-x²-5+x²)(3-x²+5-x²)=0-2*(-2x²+8)=0-2x²+8=02x²=8x²=4x=-2 U x=2