Помогите пожалуйста найти обл опр ф-ий 1) у=ln*3x+4/5-x 2) y=tg*2x-3/x+7

1y=ln[(3x+4)/(5-x)](3x+4)/(5-x)>0x=-4/3  x=5          _                     +                    _ ---------------(-4/3)--------------(5)------------------   x∈(-4/3;5) 2 y=tg[(2x-3)/(x+7)]-π/2<(2x-3)/(x+7)<π/2{(2x-3)/(x+7)>-π/2  (1){(2x-3)/(x+7)<π/2  (2)1)(2x-3)/(x+7)+π/2>0(4x-6+πx+7π)/(x+7)>0[x(4+π)+(7π-6)]/(x+7)>0x=(6-7π)/(4+π)   x=-7             +                       _                                     +------------------(-7)------------------((6-7π)/(4+π) )------------------ x<-7) U x>((6-7π)/(4+π) )2)(2x-3)/(x+7)-π/2<0(4x-6-πx-7π)/(x+7)<0[x(4-π)-(6+7π)]/(x+7)<0x=(6+7π)/(4-π)  x=-7      +                                 _                               +--------(-7)-----------------------------((6+7π)/(4-π))---------------------7<x<((6+7π)/(4-π)\\\\\\\\\\\\\                                  ////////////////////////////////////////////////////////////////////////////////---------(-7)------------------((6-7π)/(4+π))---------------------((6+7π)/(4-π))---------------------              \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\x∈([(6-7π/(4+π)];[(6+7π)/(4-π])