(2-x)/(x+1)>=4 дробное неравенство

(2-x)/(x+1)>=4
дробное неравенство
- Предмет:
  Алгебра
- Автор:
  kobegarner
- 6 лет назад

Ответы 4

Спасибо большое
- Автор:
  bridgetrodgers
- 6 лет назад
- 0
Спасибо большое
- Автор:
  bongo
- 6 лет назад
- 0
$\frac{2-x}{x+1} \geq 4 \\ \\ \frac{2-x}{x+1} -4 \geq 0 \\ \\ \frac{(2-x)-4*(x+1)}{x+1} \geq 0 \\ \\ \frac{2-x-4x-4}{x+1} \geq 0 \\ \\ \frac{(5x+2)}{x+1} \leq 0 \\ \\ 5x+2=0 \\ x=-0.4 \\ \\ x+1=0 \\ x=-1$ {5x+2≥0 ⇔ {x≥-0.4 ⇔решений нет{x+1<0 {x<-1 {5x+2≤0 ⇔ {x≤-0.4 ⇔x∈[-0.4;-1){ x+1>0 {x>-1
- Автор:
  audreymitchell
- 6 лет назад
- 0
(2-x)/(x+1)-4≥0(2-x-4x-4)/(x+1)≥0(-5x-2)/(x+1)≥0x=-0,4 x=-1 _ + _----------------(-1)-------------[-0,4]------------------x∈(-1;-0,4]
- Автор:
  billy
- 6 лет назад
- 0
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(2-x)/(x+1)>=4 дробное неравенство

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(2-x)/(x+1)>=4
дробное неравенство