1)x≤1,625x²-32+20x<80x-6425x²-32+20x-80x+64<025x²-60x+32<0D=3600-3200=400x1=(60-20)/50=0,8x2=(60+20)/50=1,6 ///////////////////////////// + _ +--------------(0,8)--------------(1,6)----------///////////////////////////////////////////////0,8<x<1,62)x>1,625x²+32-20x-80x+64<025x²-100x+96<0D=10000-9600=400x1=(100-20)/50=1,6x2=(100+20)/50=2,4 /////////////////////// + _ +--------------(1,6)-----------(2,4)---------------- \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\1,6<x<2,4Ответ x∈(0,8;1,5) U (1,6;2,4)