Решите систему уравнений
{x-y=1
{x2-y=3

x = y + 1(y + 1)^2 - y - 3 = 0 *y^2 + 2y + 1 - y - 3 = 0y^2 + y - 2 = 0D = 1 + 4*2 = 9y1 = ( - 1 + 3)/2 = 1y2 = ( - 1 - 3)/2 = - 2x1 = y1 + 1 = 1 + 1 = 2y1 = 1x2  = y2 + 1 = - 2 + 1 = - 1 y2 = - 2 Ответ ( - 1; - 2) ; ( 2; 1)