4x*2 +6x -2= (x-1)*2

4x^2 +6x-2=(x-1)^2
4x^2+6x-2=x^2-2x+1
3x^2+8x-3=0
D1=16+9=25
x1=(-4+5)/3=1/3
x2=(-4-5)/3=-3
Ответ: -3; 1/3

4x^{2} + 6x - 2 = (x-1)^{2} 
4x^{2} + 6x - 2 = x^{2} - 2x +1 
4x^{2} + 6x - 2 - x^{2} +2x - 1 = 0 
3x^{2} +8x - 3 = 0 
D = 8^{2} - 4*3*(-3) = 64 - (-36) = 100 
x_{1,2} = \frac{-8 \frac{+}{-} 10}{2*3} 
x_{1} = -3 
x_{2} = \frac{1}{3}