6-3-у/2=у-1/2+у-2/3

 (6-3-y)/2 = (у-1)/2 + (у-2)/3(3-у) /2  =  (у-1)/2 + (у-2)/3(3-у)/2 - (у-1)/2 +(у-2)/3 =03(3-у) - 3(у-1) + 2(у-2)=0*69-3у-3у+3+2у-4=0-4у +8 =0-4у=-8у= (-8) : (-4)у= 2Проверим:(6-3-2)/2 = (2-1)/2 + (2-2)/31/2 =  1/2+01/2=1/2