СРОЧНО Sin4x-cos^4x=-sin^4x

sin4x=cos^4x-sin^4xsin4x=(cos²x-sin²x)(cos²x+sin²x)sin4x=cos2x2sin2xcos2x-cos2x=0cos2x*(2sin2x-1)=0cos2x=0⇒2x=π/2+πk⇒x=π/4+πk/2,k∈z2sin2x=1sin2x=1/22x=π/6+2πk U 2x=5π/6+2πk,k∈zx=π/12+πk U x=5π/12+πk,k∈z