Решить неравенства:
1) [tex]tgx\ \textgreater \ \frac{1}{ \sqrt{3} } [/tex]
2)[tex]tg2x \geq \frac{1}{ \sqrt{3} } [/tex]
3) [tex]tg \frac{x}{6} \ \textless \ \frac{1}{ \sqrt{3} } [/tex]
4) [tex]tg(x- \frac{ \pi }{9} ) \leq - \frac{1}{ \sqrt{3} } [/tex]

йог

1tgx>1/√3x∈(π/6+πk;π/2+πk,k∈z)2tg2x≥1/√3π/6+πk≤2x≤π/2+πk,k∈zx∈[π/12+πk/2;π/4+∈z)3tgx/3<1/√3-π/2+πk<x/3<π/6+πk,k∈z-3π/2+3πk<x<π/2+3πk,k∈z4tg(x-π/9)≤-1/√3-π/2+πk≤x-π/9≤-π/6+πk,k∈z-π/2+π/9+πk≤x≤-π/6+π/9+πk,k∈z-7π/18+πk≤x≤-π/18+πk,k∈z