25^х=5 ^3 - х
3 sin ^2 2x+10sin 2x+3=0

25^x = 5^(3 - x)5^(2x) = 5^(3 - x)2x = 3 - x2x + x = 33x = 3x = 13sin²2x + 10sin2x + 3 = 03sin²2x + 9sin2x + sin2x + 3 = 03sin2x(3sin2x + 3) + (sin2x + 3) = 0(3sin2x + 1)(3sin2x + 3) = 01) 3sin2x = -1sin2x = -1/32x = (-1)ⁿ⁺¹arcsin(1/3) + πn, n ∈ Zx =  1/2·(-1)ⁿ⁺¹arcsin(1/3) + πn/2, n ∈ Z2) 3sin2x = -3sin2x = -12x = -π/2 + 2πk, k ∈ Zx = -π/4 + πk, k ∈ Z