(2x-1)2 + (2x+1)*(2x-1)

(2x-1)^2 + (2x+1)*(2x-1)4x^2 - 4x + 1 + 4x^2 - 18x^2 - 4x = 0 4x(2x-1) = 04x = 0 и 2x - 1 = 0x = 0 и 2x = 1            x = 1/2Или же, если (2x-1)*2(2x-1)2 + (2x+1)*(2x-1)4x - 2 + 4x^2 - 14x^2 + 4x -  3 = 04x^2/4 + 4x - 3*4 = 0x -> aa^2 + 4a - 12 = 0a1 = -6a2 = 2 x1 = -6/4 = -3/2 x2 = 2/6 = 1/3