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Нужно подробно разъяснить
1.)
5х+(3х-7)=9
б)3у-(5-у)=11
в)48=11-(9а+2)
г)13-(5х+11)=6х

2.)а)(7х+1)-(6х+3)=5
б)(8х+11)-13=9х-5
в)2=(3х-5)-(7-4х)
г)8х+5=119+(7-3х)

Спасибо большое!

1a) 5x + (3x - 7) = 9     б) 3y - (5 - y) = 11    в) 48 = 11 - (9a + 2)          5x + 3x - 7 = 9                  3y - 5 + y = 11         48 = 11 - 9a - 28x = 9 + 7                          4y = 11 + 5             9a = 9 - 488x = 16                              4y = 16                   9a = - 39x = 2                                     y = 4                    a = - (4)1/3г)13 - (5x + 11)= 6x13 - 5x - 11 = 6x- 5x - 6x = 11 - 13- 11x = - 2      x = 2/112a) (7x + 1) - (6x + 3) = 57x + 1 - 6x - 3 = 5x = 5 - 1 + 3x = 7б)(8x + 11) - 13 = 9x - 58x + 11 - 13 = 9x - 58x - 9x = - 5 - 11 + 13- x = - 3x = 3в) 2 = (3x - 5) - (7 - 4x)2 = 3x - 5 - 7 + 4x- 3x - 4x = - 5 - 7 - 2- 7x = - 14x = 2г) 8x + 5 = 119 + (7 - 3x)8x + 5 = 119 + 7 - 3x8x + 3x = 119 + 7 - 511x = 121x = 11