Найдите нули функции:
a)y =2x-0,3
b)3x^2-7x+4

a) y = 2x - 0,32x - 0,3 = 02x = 0,3x = 0,15b) 3x² - 7x + 4 = 0D = 7² - 4 * 3 * 4 = 49 - 48 = 1X1,2 = (7 + - √1) / 6 = (7 + - 1) / 6X1 = (7 + 1) / 6 = 8/6 = (1)1/3X2 = (7 - 1) /6 = 6/6 = 1