Дано: sin(4π+t)=3/5, 0<t<π/2. Вычислите tg(π-t).

sin(4π+t)=3/5, 0<t<π/2tg(π-t)-?sin(4π+t)=sint=3/5tg(π-t)=-tgt-tgt=-sint/costcos=√1-sin²t=√1-9/25=√16/25cost=4/5-tgt=-3/5*5/4=-3/4

Sin(4π + t) = 3/5Sint = 3/5Cost = + - √(1 - Sin²t) Так как t - угол первой четверти, тоCost = √(1 - Sin²t) = √( 1 - 9/25) = √16/25 = 4/5tg(π - t) = - tgt = - Sint/Cost = - 3/5 : 4/5 = - 3/4 = - 0,75