help me!!!!!!
(x^4-1)^3-(x^4-1)^2=0
(x+1)^3-(x+1)+x+1=0

x^4-1=tt^3-t^2=0t^2(t-1)=0t=0t=1x^4-1=0x^4=1x=+-1x^4-1=1x^4=2x=+- корень 4 степени из 2x+1=tt^3-t+t=0t^3=0t=0x+1=0x=-1