(x+1)^2+(y-3)^2 <9
Срочно! Помогите пожалуйста

(x+1)²+(y-3)²<9(y-3)²+(x+1)²-9<0x²+2x+1+y²-6y+9-9<0x²+2x+y²-6y+1<0x²+2x+y²-6y+1=0D=√(4-4*(y²-6y+1))=√(4-4y²+24y-4)=√(24y-4y²)=2*√(6y-y²)x₁=(-2-2√(6y-y²)/2=-(√(6y-y²)-1x₂=√(6y-y²)-1(x-√(6y-y²)+1)*(x+√(6y-y²)+1)<0Так как 6y-y²≥0 ⇒-∞____+____-√(6y-y²)-1____-____√(6y-y²)-1_____+_____+∞x∈((-√(6y-y²)-1);((√(6y-y²)-1)).