[tex] \sqrt{3} sin2x-cos2x-2=0 [/tex]

2√3sinxcosx-cos²x+sin²x-2sin²x-2cos²x=0sin²x-2√3sinxcosx+3=0 /cos²xtg²x-2√3tgx+3=0(tgx-√3)²=0tgx-√3=0tgx=√3x=π/3+πk,k∈z