решите уравнение (1-2х)^4-5(1-2x)^2=4

замена t=(1-2x)^2, t>=0t^2-5t-4=0D=41t=(5+-sqrt(41))/2(5-sqrt(41))/2<0 - пост. корень(1-2x)^2=(5+sqrt(41))/2(1-2x-sqrt((5+sqrt(41))/2))(1-2x+sqrt((5+sqrt(41))/2)=0x1=(1-sqrt((5+sqrt(41))/2))/2x2=(1+sqrt((5+sqrt(41))/2))/2