tg²x-36tgx+68=0 пліз поможіть

tg^2x - 36tgx + 68 = 0 tgx = y y^2 - 36y + 68 =0a = 1 b = - 36 c = 68D=b^2 - 4acD = 1296 - 272 = 1024 = 32^2 x1.2 = (-b +/- D)/2a x1= 36 + 32/2 = 68/2 = 34x2= 36-32/2 = 4/2 = 2tgx=y1) tgx = 34x = arctg34  + Пn 2) tgx = 2 x = arctg2 + Пn