Решите уравнение:
2x^2-3x+5/6x+10 + 1,5x+2,5/2x^2-3x+5 = 1

(2x^2-3x+5)/(6x+10) + (1,5x+2,5)/(2x^2-3x+5 )= 1(2x^2-3x+5)/(6x+10) + (6x+10)/4(2x^2-3x+5) = 16x+10≠0⇒x≠-5/3(2x^2-3x+5)(/6x+10) =tt+1/4t=14t²-4t+1=0(2t-1)²=02t-1=0t=1/2(2x²-3x+5)/(6x+10)=1/24x²-6x+10=6x+104x²-12x=04x(x-3)=0x=0x=3