(x^2+2x)^2-(x+1)^2-55=0
Решите уравнение

(x^2+2x)^2-(x+1)^2-55=0(x²+2x)²-(x²+2x+1)²-55=0x²+2x=tt²-(t+1)²-55=0t²-t²-2t-1-55=02t=-56t=-28x²+2x=28x²+2x-28=0D=4+112=116x1=(-2-2√29)/2=-1-√29 U x2=-1+√29