если график функции y=kx-6 проходит через точку А(-50;-4), то k равно - №27633921

если график функции y=kx-6 проходит через точку А(-50;-4), то k равно
- Предмет:
  Алгебра
- Автор:
  avaokoz
- 5 лет назад

Ответы 2

y=kx - 6, A(-50; -4)-50k - 6 = -4-50k= 2k= 2/(-50)k=-0,04
- Автор:
  aryanahardin
- 5 лет назад
- 0
$y=kx-6\\a(-50;-4)\\-4=-50k-6\\-50k=2\\k=-2/50=-1/25=-0,04$
- Автор:
  may
- 5 лет назад
- 0
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