sin4x-sinx=0
Найти кони на промежутке [tex][ \pi ; \frac{5 \pi }{2} ][/tex]

2sin(3x/2)cos(5x/2)=0sin(3x/2)=03x/2=πkx=2πk/3,k∈zπ≤2πk/3≤5π/26≤4k≤156/4≤k≤15/4k=2  x=4π/3k=3  x=2πcos(5x/2)=05x/2=π/2+πkx=π/5+2πk/5π≤π/5+2πk/5≤5π/210≤2+4k≤258≤4k≤232≤k≤23/4k=2  x=πk=3  x=7π/5k=4  x=9π/5k=5  x=11π/5