Решите систему уравнений! Срочно! [tex] \left \{ {{ \sqrt{xy} * ( \sqrt{x} + \sqrt{y} )=6}

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$\left \{ {{\sqrt{xy}\cdot (\sqrt{x}+\sqrt{y})=6} \atop {(\sqrt{x}+\sqrt{y})(x-\sqrt{xy}+y)=9}} ight. \; ,\; \; u=\sqrt{x}+\sqrt{y}\; ,\; \; v= \sqrt{xy}\\\\ODZ:\; \; x\geq 0\; ,\; y\geq 0\\\\x+y=(\sqrt{x}-\sqrt{y})^2-2\sqrt{xy}\\\\ \left \{ {{uv=6} \atop {u(u^2-3v)=9}} ight. \; \left \{ {{v=\frac{6}{u}} \atop {u(u^2-3\cdot \frac{6}{u})=9}} ight. \; \left \{ {{v=\frac{6}{u}} \atop {u^3=27}} ight. \; \left \{ {{v=2} \atop {u=3}} ight. \; \left \{ {{\sqrt{xy}=2} \atop {\sqrt{x}+\sqrt{y}=3}} ight. \\\\t=\sqrt{x}\; ,\; p=\sqrt{y}$ $\left \{ {{tp=2} \atop {t+p=3}} ight. \; \left \{ {{t(3-t)=2} \atop {p=3-t}} ight. \; \left \{ {{t^2-3t+2=0} \atop {p=3-t}} ight.\; \left \{ {{t_1=1\; ,\; t_2=2} \atop {p_1=2\; ,\; p_2=1}} ight. \\\\ \left \{ {{ \sqrt{x}=1} \atop { \sqrt{y}=2}} ight. \; \; \; ili\; \; \; \left \{ {{\sqrt{x}=2} \atop {\sqrt{y}=1}} ight. \\\\\left \{ {{x=1} \atop {y=4}} ight. \; \; \; ili\; \; \; \left \{ {{x=4} \atop {y=1}} ight.\\\\Otvet:\; \; (1,4)\; ,\; (4,1)\; .$
- Автор:
  chessieie62
- 5 лет назад
- 0
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