• [tex] \left \{ {{3 ^{x+y} =27} \atop {(x-y) ^{2} =1}} ight. [/tex]

Ответы 1

  •  \left \{ {{3^{x+y}=27} \atop {(x-y)^2=1}} ight. \\ \left \{ {{3^{x+y}=3^3} \atop {(x-y)^2=1}} ight. \\ \left \{ {{x+y=3} \atop {(x-y)^2=1}} ight. \\ \left \{ {{x=3-y} \atop {(3-y-y)^2=1}} ight. \\  \left \{ {{x=3-y} \atop {3-2y=б1}} ight. \\ \left \{ {{x=3-y} \atop {y= \frac{3б1}{2} }} ight. \\ \\ \\ \left \{ {{x=3-y} \atop {y=1 }} ight. \\ \left \{ {{x=3-y} \atop {y=2 }} ight. \\ \\  \\ \left \{ {{x=2} \atop {y=1 }} ight. \\ \left \{ {{x=1} \atop {y=2 }} ight. \\ \\ OTBET:(1;2),(2;1)
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