[tex]2 \sqrt{6} [/tex] sin8п/3*cos25п/4 помогите пожалуйста умоляю
вычислите

2*√6*sin(8π/3)*cos(25π/4)=3.1) sin(8π/3)=8*180°/3=sin480°=sin(360°+120°)=sin120°=√3/2.2) cos(25π/4)=cos(25*180°/4)=cos(25*45°)=cos1125°==(3*360+45°)=cos45°=√2/2.3) 2*√6*(√3/2)*(√2/2)=2*√6*√6/4=6/2=3.