Решить уравнения 1)3(x+1)=18. 2)(y-5)(y-8)=y^2+1. 3)(3x+2)(4x-1)-(6x+2)(2x-1)=0

3(х + 1) = 183х + 3 = 183х = 18 - 33х = 15  х = 5------------------------------(у - 5)(у - 8) = у^2 + 1y^2 - 5y - 8y + 40 = y^2 + 1- 13y + 40 = 1- 13y = - 40 + 1- 13y = - 39      y = 3-----------------------------(3x + 2)(4x - 1) - (6x + 2)(2x - 1) = 0(12x^2 + 8x - 3x - 2 ) - (12x^2 + 4x - 6x - 2) = 012x^2 + 5x - 2 - 12x^2 + 2x + 2 = 07x = 0  x = 0---------------------------- 

1) 3(х+1)=183х+3=183х=18-33х=15х=53) (3х+2)(4х-1)-(6х+2)(2х-1)=012х(х во второй степени)-3х+8х-2-12х(х во 2 степени)+6х+4х-2=0-3х+8х+6х+4х=2+215х=4х=0,26