Пооомогите пожалуйста что 353 второй пример и 354 тоже 2 пример

Ответы 1

$353.2)\; \; \frac{\sqrt{2x-1}-1}{x}\ \textless \ 0\; \; \; \Rightarrow \\\\a)\; \left \{ {{\sqrt{2x-1}-1\ \textless \ 0\; ,\; 2x-1 \geq 0} \atop {x\ \textgreater \ 0}} ight. \; \; ili\; \; b)\; \left \{ {{\sqrt{2x-1}-1\ \textgreater \ 0\; ,\; 2x-1 \geq 0} \atop {x\ \textless \ 0}} ight. \\\\ \left \{ {{\sqrt{2x-1}\ \textless \ 1\; ,\; x \geq \frac{1}{2}} \atop {x\ \textgreater \ 0}} ight. \quad ili\quad \left \{ {{\sqrt{2x-1}\ \textgreater \ 1\; ,\; x \geq \frac{1}{2}} \atop {x\ \textless \ 0}} ight. \\\\ \left \{ {{2x-1\ \textless \ 1} \atop {x \geq \frac{1}{2}}} ight. \qquad ili\qquad \left \{ {{2x-1\ \textgreater \ 1} \atop {x\ \textless \ 0\; ,\; x\geq \frac{1}{2}}} ight.$ $\left \{ {{2x\ \textless \ 2} \atop {x\geq \frac{1}{2}}} ight. \qquad ili\qquad x\in \varnothing \\\\ \left \{ {{x\ \textless \ 1} \atop {x \geq \frac{1}{2}}} ight. \; \; \Rightarrow \; \; \; \frac{1}{2} \leq x\ \textless \ 1\\\\Otvet:\; \; x\in [\, \frac{1}{2},1)\; .$ $354.2)\; \; \frac{x^2+6x+9}{2^{x}-4}\ \textgreater \ 0\; \; \Rightarrow \; \; \frac{(x+3)^2}{2^{x}-4}\ \textgreater \ 0\\\\Tak\; kak\; \; \; (x+3)^2 \geq 0\; \; i\; \; \frac{(x+3)^2}{2^{x}-4}\ \textgreater \ 0,\; \; to \; \; (2^{x}-4)\ \textgreater \ 0\; \; \to \; \; 2^{x}\ \textgreater \ 4\; ,\\\\2^{x}\ \textgreater \ 2^2\; \; \to \; \; \underline {x\ \textgreater \ 2}$
- Автор:
  josafatfuller
- 5 лет назад
- 0
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