Решите уравнения:
8x(1+2x)-(4x+3)(4x-3)=2
(8-9x)x=-40+(6-3x)(6+3x)
(x-6)²-x(x+8)=2
16x(2-x)+(4x-5)²=1
9x²-1-(3x-2)²=0
(4x-3)(3+4x)-2x(8x-1)=0

4) 32х-16х^2+(16х^2+40+25) = 132х-16х^2+16х^2+40+25 = 132х = 64х = 25) 9х^2-1-(9х^2+12+4) = 09х^2-1-9х^2-12-4 = 0-1-16 = 0-17 = 06) 16х^2-9-16х^2+2х = 02х-9 = 0х = 4,5