1) (Х^2+5Х)/(Х+3)=4 

2) (2Х+3)/(Х+2)=(3Х+2)/Х 

1)(х²+5х)/(х+3)=4 х≠-3х²+5х-4(х+3)=0х²+5х-4х-12=0х²+х-12=0Д=1+48=7²х1=-1+7/2=3х2=-1-7/2=-4х1=3, х2=-42)(2х+3)/(х+2)=(3х+2)/х х≠-2 х≠0(2х+3)х-(3х²+6х+2х+2)=02х²+3х-3х²-8х-4=0х²+5х+4=0Д=25-16=3²х1=-5+3/2=-1х2=-5-3/2=-4х1=-1, х2=-4,х≠-2, х≠0.