3(x-4)^2-3x^2 решите

3(x-4)^2-3x^2=3((x-4)^2-x^2)=3(x-4-x)(x-4+x)=3*(-4)*(2x-4)=-12(2x-4)=-24x+483(x-4)^2-3x^2=3(x^2-8x+16)-3x^2=3x^2-24x+48-3x^2=-24x+48