Помогите пожалуйста! [tex]( \sqrt{ \sqrt{3}+ \sqrt{2} } - \sqrt{ \sqrt{3}- \sqrt{2} } )*(

Ответы 1

$(\sqrt{\sqrt{3}+\sqrt{2}}-\sqrt{\sqrt{3}-\sqrt{2}})*(\sqrt{\sqrt{3}+\sqrt{2}}+\sqrt{\sqrt{3}-\sqrt{2}}) ^{-1} +\sqrt{\sqrt{(\sqrt{5}-\frac{5}{2})^{2}}-\sqrt[3]{(\frac{3}{2}-\sqrt{5)}^{3}}}}=\\\ =\frac{\sqrt{\sqrt{3}+\sqrt{2}}-\sqrt{\sqrt{3}-\sqrt{2}}}{\sqrt{\sqrt{3}+\sqrt{2}}+\sqrt{\sqrt{3}-\sqrt{2}}} +\sqrt{|\sqrt{5}-\frac{5}{2}|-\frac{3}{2}+\sqrt{5)}}=\\\$ $=\frac{\sqrt{\sqrt{3}+\sqrt{2}}-\sqrt{\sqrt{3}-\sqrt{2}}}{\sqrt{\sqrt{3}+\sqrt{2}}+\sqrt{\sqrt{3}-\sqrt{2}}} +\sqrt{\frac{5}{2}-\sqrt{5}-\frac{3}{2}+\sqrt{5}}=\\\ =\frac{\sqrt{\sqrt{3}+\sqrt{2}}-\sqrt{\sqrt{3}-\sqrt{2}}}{\sqrt{\sqrt{3}+\sqrt{2}}+\sqrt{\sqrt{3}-\sqrt{2}}} +1=\frac{(\sqrt{\sqrt{3}+\sqrt{2}}-\sqrt{\sqrt{3}-\sqrt{2}})^2}{(\sqrt{\sqrt{3}+\sqrt{2}}+\sqrt{\sqrt{3}-\sqrt{2}})(\sqrt{\sqrt{3}+\sqrt{2}}-\sqrt{\sqrt{3}-\sqrt{2}})} +1=\\\$ $=\frac{(\sqrt{\sqrt{3}+\sqrt{2}})^2-2\sqrt{\sqrt{3}+\sqrt{2}}*\sqrt{\sqrt{3}-\sqrt{2}}+(\sqrt{\sqrt{3}-\sqrt{2}}))^2}{(\sqrt{\sqrt{3}+\sqrt{2}})^2-(\sqrt{\sqrt{3}-\sqrt{2}})^2} +1=$ $=\frac{\sqrt{3}+\sqrt{2}-2+\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}-\sqrt{3}+\sqrt{2}}+1\\\ =\frac{2\sqrt{3}-2}{2\sqrt{2}}+1=\frac{2\sqrt{3}-2+2\sqrt{2}}{2\sqrt{2}}=\frac{\sqrt{3}-1+\sqrt{2}}{\sqrt{2}}$
- Автор:
  zaiddavila
- 5 лет назад
- 0
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