Здравствуйте, помогите, пожалуйста, решить. Мое решение не сходится с ответом

sin5x - cos4x = 0sin5x - sin(pi/2 - 4x) = 02*sin(5x - pi/2 + 4x)/2 * cos(5x + pi/2 - 4x)/2 = 0sin (9x - pi/2)/2 * cos(x + pi/2)/2 = 0sin(4,5x - pi/4) * cos(0,5x + pi/4) = 01) sin(4,5x - pi/4)  = 04,5x - pi/4 = pik4,5x = pi/4  + pikx = pi/18 + (2pik)/92) cos(0,5x + pi/4) = 00,5x + pi/4 = pi/2 + pik0,5x = pi/2 - pi/4 + pik0,5x = pi/4 + pikx = pi/2 + 2pikОтбор корней1) 2pi <= pi/18 + 2pik/9 <= 3pi2 <= 1/18 + 2k/9 <= 32 - 1/18 <= 2k/9 <= 3 - 1/181,94 <= 2k/9 <= 2,948,81 <= k <= 13,22 k = 9; 10; 11; 12; 13k = 9 ==> pi/18 + 2pi*9/9 = pi/18 + 2pi = 37pi/18k = 10 ==> pi/18 + 2pi*10/9 = pi/18 + 20pi/9 = 41pi/18k= 11 ==> pi/18 + 2pi*11/9 = pi/18 + 22pi/9 = 5pi/2k = 12 ==> pi/18 + 2pi*12/9 = pi/18 + 24pi/9 = 49pi/18k = 13 ==> pi/18 + 2pi*13/9 = pi/18 + 26pi/9 = 53pi/182) 2pi <= pi/2 + 2pik <= 3pi2 <= 1/2 + 2k <= 31,5 <= 2k <= 2,50,75 <= k <= 1,25k = 1k = 1 ==> pi/2 + 2pi*1 = pi/2 + 2pi = 5pi/2ОТВЕТа) x1 = pi/18 + (2pik)/9;x2 = pi/2 + 2pikб) 37pi/18;  41pi/18 ; 5pi/2 ; 49pi/18 ; 53pi/18