а) 2(12x²+x-10)=-5 24x²+2x-20=-5 24x²+2x-15=0D=b²-4ac=4-4×24×(-15)=4+1440=1444 √1444=38x₁=͟ ͟͟-͟2͟͟͟-͟͟3͟͟8 = ͟-͟4͟0͟ = -1 48 40 x₂= ͟-͟2͟+͟3͟͟8͟ = ͟3͟6 = 0,9 40 40Ответ:x₁=-1; x₂=0,9.б) 5(x²-2)=x(1-x)+10x 5x²-10=x-x²+10x 5x²+x²-x-10x-10=0 6x²-11x-10=0D=b²-4ac=(-11)²-4×6×(-10)=121+160=361 √361=19x₁= ͟1͟1͟-͟͟1͟9 = ͟͟-͟8͟ = ͟-͟2͟͟ 12 12 3x₂= ͟1͟1͟+͟1͟9͟͟ = ͟3͟0͟ = ͟5͟ = 2,5 12 12 6 Ответ: x₁= ͟-͟2͟ ; x₂= 2,5.в) (2x+3)²+2x²=-12x-(x-2)² 4x+9+2x²= -12x-x²+4 2x²+x²+4x+12x+9x-4=0 3x²+16x+5=0D=b²-4ac=16²-4×3×5=256-60=196 √196=14x₁= ͟͟-͟1͟6͟͟-͟1͟͟4͟ = ͟-͟3͟0͟ = -5 6 6x₂= ͟-͟1͟6͟+͟1͟4͟ = ͟-͟2͟ = ͟-͟1͟ 6 6 3Ответ: x₁= -5; x₂= ͟-͟1͟ . 3