x²-3xy+3y-x=2, розвяжите в целых числах, умоляю помогите!

x^2 - x - 3xy + 3y = 2x (x - 1) - 3y(x - 1) = 2(x - 1)*(x - 3y) = 2 y = 0;  ± 1; ± 2Если y = 0(x - 1)*x = 2x^2 - x - 2 = 0D = 1 + 4*2 = 9x1 = ( 1 + 3)/2 = 4/2 = 2x2 = (1 - 3)/2 = - 2/2 = - 1ОТВЕТ( - 1; 0) ; (2; 0)