найдите значение алгебраического выражения:6x^2-6y^2/5(x-y)(x+y),если x=-3;y=2

найдите значение алгебраического выражения:6x^2-6y^2/5(x-y)(x+y),если x=-3;y=2
- Предмет:
  Алгебра
- Автор:
  bernabé
- 5 лет назад

Ответы 1

Упростим алгебраическое выражение: $\frac{6x^2-6y^2}{5(x-y)(x+y)} = \frac{6(x^2-y^2)}{5(x^2-y^2)} = \frac{6}{5} =1.2$ значение данного выражения не зависит от значения переменной х.Проверим на полном выражении: $x = - 3 ; y = 2 \\ \\ \frac{6*(-3)^2-6* 2^2}{5(-3-2)(-3+2)} = \frac{6*9 - 6*4}{5*(-5)*(-1)}= \frac{54-24}{25} = \frac{30}{25} = \frac{6}{5} =1.2$ Ответ: 1,2 .
- Автор:
  ty
- 5 лет назад
- 0
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найдите значение алгебраического выражения:6x^2-6y^2/5(x-y)(x+y),если x=-3;y=2

Ответы 1

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