[tex] 1)\frac{x + 2}{3} - 4x = 8 \\ 2)(3x + 1)^{2} - 9(x + 1) \times (x - 1) = 0[/tex]
Решите уравнения

1) x+2/3 - 4x=8x+2-12x=24-11x+2=24-11x=24-2-11x=22x=-22)(3x+1)^2-9(x+1)(x-1)=09x^2 +6x+1-9(x^2 -1)=09x^2+6x+1-9x^2+9=06x+10=06x=-10x=- 5/3