Решите неравенства (х+3)(2х^2-7х+5)<0

(х+3)(2х^2-7х+5)<02х^2-7х+5=0    √D=√49-40=3   x1=1/4[7-3]=1   x2=1/4[7+3]=2.52х^2-7х+5=(x-1)(x-2.5)(х+3)(x-1)(x-2.5)<0-------------- -3--------------- 1-------------------- 2.5-----------------      -                     +                          -                         +x(-∞;-3)∪(1;2.5)