2x/x+3 + 1/x-1 = 4/x^2+2x-3

решите уравнение

2x/x+3 + 1/x-1 = 4/x^2+2x-3x≠-3x≠12x/x+3+1/x-1-4/x²+2x-2=02x/x=3+1/x-1-4/x²+3x-x-3=02x/x+3+1/x-1-4/x(x+)-(x+3)=02x/x+3+1/x-1-4/(x+3)(x-1)=02x²-2x+x+3-4/(x+3)(x-1)=02x²+x-2x-1/(x+3)(x-1)=0x(2x+1)-(2x+1)/(x+3)(x-1)=0(2x+1)(x-1)/(x+3)(x-1)=02x+1/x+3=02x+1=02x=-1x=-1/2x≠-3x≠1x=-1/2