1) 5y+1 / y + 1 = y+2 / 2
2) y(в квадрате )/ y + 3= y / y+3

1) 5y+1/y+1=y+2/25y+1/y+1=y+2+2, y≠-12(5y+1)=(y+2)(y+1)2(5y+1)-(y+2)(y+1)=010y+2-(y²+y+2y+2)=010y+2-(y²+3y+2)=010y+2-y²-3y-2=07y-y=0y(7-y)=0y=07-y=0y=0y=7,  y≠-1y₁=0y₂=7