4C(x+2) по (x-1) = 4(x+2)!/(3!*(x-1)!) = 4(x-1)!*x(x+1)(x+2)/(6(x-1)!) = 4x(x+1)(x+2)/6 = 2x(x+1)(x+2)/3 A 3 x = x!/(x-3)! = (x-2)(x-1)x Значит 2x(x+1)(x+2)/3 = (x-2)(x-1)x 2x(x+1)(x+2) = 3(x-2)(x-1)x x(2(x+1)(x+2)-3(x-2)(x-1))=0 x=02(x+1)(x+2)-3(x-2)(x-1)=0 2(x^2+3x+2)-3(x^2-3x+2)=0 2x^2+6x+4-3x^2+9x-6=0 -x^2+15x-2=0 x^2-15x+2=0 D=217 x=(15+/-√217)/2 Ответ x=0, x=(15+/-√217)/2