Решите уравнения( ^ - степень):
1)169х^3-26х^2+х=0
2)х^3-2х^2-25х+50=0

1)В первом уравнении один корень х=0.                                                          Сократив на х получим квадратное169х*х-26х+1=0                                удобно 13х=у                                                                                 у*у-2у+1=0                                                            у=1                                        х=1/13                                                           Два решения х=0 и х=1/13                                                   2) сразу видим х=2                                                                    Поделим на (х-2)                                                 х*х+ах-25=0                                                              а=0                                                                  х*х-25=0                                                              х=5 или х=-5                                          Ответ: х=2 или х=5 или х=-5