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log7(5x+x)=log7(5x-3) x принадлежит (3/5;+бесконечности)5+x=5x-3x-5x=-5-3-4x=-8x=2Ответ:x=2
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Автор:
gunther - 5 лет назад
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Даны векторы:
a=(2,3,0); b=(-6,0,1); c=(5,1,-1)
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