решить уравнение cos(1,5п-2x)-cosx=0

cos(1.5π-2x) = -sin2x-sin2x - cosx = 0-2sinxcosx - cosx =0-cosx*(2sinx + 1) =0cosx=0, x = π/2+πn2sinx +1 =0, sinx=-1/2, x= (-1)^k+1 *π/6 + πk

Вот полностью напиши!sin2x-sin(π/2-x)=02sin(3x/2-π/4)cos(x/2+π/4)=0sin(3x/2-π/4)=03x/2-π/4=πn3x/2=π/4+πnx=π/6+2πn/3cos(x/2+π/4)=0x/2+π/4=π/2+πnx/2=π/4+πnx=π/2+2πn