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Найдите наибольшее значение функции
f(x)=log6(x-2) на отрезке (3,8)
Ответы 1
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f'(x)=1/((x-2)ln6)≠0 ⇒ наибольшее и наименьшее значение на концах отрезкаy(3)=log6(3-2)=log6 (1)=0y(8)=log6(8-2)=log6(6)=10 - наименьшее значение1-наибольшее
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Автор:
kingston - 6 лет назад
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