Если tga=5/12 и п<a<3п/2 Найти sina=? - №29280782

Если tga=5/12 и п<a<3п/2 Найти sina=?
- Предмет:
  Алгебра
- Автор:
  alonsoxyye
- 6 лет назад

Ответы 1

1+tg^2a=1/cos^2a; cos^2a=1/1+tg^2a; cos^2a=1/25+144; cos^2a=144/169 cosa=+-12/13. sina=tgacosa = +-5/13
- Автор:
  trippiq1c
- 6 лет назад
- 0
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